10z^2-9z+2=0

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Solution for 10z^2-9z+2=0 equation:



10z^2-9z+2=0
a = 10; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·10·2
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-1}{2*10}=\frac{8}{20} =2/5 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+1}{2*10}=\frac{10}{20} =1/2 $

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